(1/9)^5x+1/2=27^3x-2

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Solution for (1/9)^5x+1/2=27^3x-2 equation: 



(1/9)^5x+1/2=27^3x-2

We move all terms to the left:

(1/9)^5x+1/2-(27^3x-2)=0



Domain of the equation: 9)^5x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)^5x-(27^3x-2)+1/2=0

We get rid of parentheses

(+1/9)^5x-27^3x+2+1/2=0

We calculate fractions


-27^3x+()/9^5x*2)+9x/9^5x*2)+2=0

We can not solve this equation

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